- 题解
DAY2 题解
- @ 2026-8-2 20:11:02
T1
#include<bits/stdc++.h>
using namespace std;
int n;
int a[10], b[10], c[10];
bool to[10];
int ans = 0;
void dfs(int t){
if(t > n) {
int sum = 0;
for(int i = 1; i < n; i++){
sum ^= b[i] + b[i+1];
}
ans = max(ans, sum);
return ;
}
for(int i = 1; i <= n; i++){
if(to[i]) continue;
to[i] = 1;
b[t] = a[i];
dfs(t+1);
to[i] = 0;
}
}
int main(){
cin >> n;
for(int i = 1; i <= n; i++){
cin >> a[i];
}
dfs(1);
cout << ans;
return 0;
}
T2
#include<bits/stdc++.h>
using namespace std;
const int N=1e3+10;
int n,m,c,a[N][N],s[N][N],x,y,sum=-1e9;
int main(){
ios::sync_with_stdio(false);
cin.tie(0);
cin>>n>>m>>c;
for(int i=1;i<=n;i++){
for(int j=1;j<=m;j++){
cin>>a[i][j];
s[i][j]=a[i][j]+s[i-1][j]+s[i][j-1]-s[i-1][j-1];
}
}
for(int i=1;i<=n;i++){
for(int j=1;j<=m;j++){
if(s[i+c-1][j+c-1]-s[i+c-1][j-1]-s[i-1][j+c-1]+s[i-1][j-1]>sum){
x=i;
y=j;
sum=s[i+c-1][j+c-1]-s[i+c-1][j-1]-s[i-1][j+c-1]+s[i-1][j-1];
}
}
}
cout<<x<<" "<<y;
return 0;
}
T3
#include<bits/stdc++.h>
using namespace std;
int a[200007], d[200007], s[200007];
int main(){
int n, k, q;
cin >> n >> k >> q;
for(int i = 1; i <= n; i++){
int l, r;
cin >> l >> r;
d[l]++;
d[r + 1]--;
}
for(int i = 1; i <= 200000; i++){
a[i] = a[i - 1] + d[i];
s[i] = s[i - 1];
if(a[i] >= k){
s[i]++;
}
}
while(q--){
int l, r;
cin >> l >> r;
cout << s[r] - s[l - 1] << '\n';
}
return 0;
}
T4
#include<bits/stdc++.h>
using namespace std;
char a[2001][2001];
int s[2001][2001];
int get(int x,int y,int xx,int yy){
return s[xx][yy]-s[xx][y-1]-s[x-1][yy]+s[x-1][y-1];
}
int n,m;
bool check(int c){
int cnt=0;
for(int i=1;i+c-1<=n;i++){
for(int j=1;j+c-1<=n;j++){
if(get(i,j,i+c-1,j+c-1)==0){
cnt++;
}
}
}
return cnt>=m;
}
int main(){
cin>>n>>m;
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
cin>>a[i][j];
if(a[i][j]=='#')s[i][j]++;
s[i][j]+=s[i][j-1]+s[i-1][j]-s[i-1][j-1];
}
}
if(n*n-s[n][n]<m){
cout<<-1;
return 0;
}
if(n*n-s[n][n]==m){
cout<<1;
return 0;
}
int l=1,r=n*n;
while(l<r){
int mid = (l+r+1)/2;
if(check(mid))l=mid;
else r=mid-1;
}
cout<<l;
return 0;
}
T5
#include<bits/stdc++.h>
using namespace std;
int a[55][55];
int s[55][55], to[25005];
int f(int x1, int y1, int x2, int y2){
return s[x2][y2] - s[x1-1][y2] - s[x2][y1-1] + s[x1-1][y1-1];
}
int main(){
int n;
cin >> n;
for(int i = 1; i <= n; i++){
for(int j = 1; j <= n; j++){
cin >> a[i][j];
s[i][j] = s[i-1][j] + s[i][j-1] - s[i-1][j-1] + a[i][j];
// cout <<s[i][j] << " ";
}
}
for(int x1 = 1; x1 <= n; x1++){
for(int y1 = 1; y1 <= n; y1++){
for(int x2 = x1; x2 <= n; x2++){
for(int y2 = y1; y2 <= n; y2++){
int t = (x2 - x1 + 1) * (y2 - y1 + 1);
to[t] = max(to[t], f(x1, y1, x2, y2));
}
}
}
}
int q;
cin >> q;
for(int i = 1; i <= n*n; i++) to[i] = max(to[i], to[i-1]);
while(q--){
int p;
cin >> p;
cout << to[p] << "\n";
}
return 0;
}
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